TNPSC Group 1 · 2017 Preliminary Examination
180.
\(1^2+2^2+2^2=3^2\)
\(2^2+3^2+6^2=7^2\)
\(3^2+4^2+12^2=13^2\) எனில்
\(6^2+7^2+42^2=?\)
Answer:
C.
\(43^2\)