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TNPSC Group 4 · 2019

198.  If \(a_1 = -1\) then find \(a_2,\ a_3\) in \(a_n = \dfrac{a_{n-1}}{n+2},\ n>1\ \forall\ n \in \mathbb{N}\).

Answer: D.   \(\dfrac{-1}{4},\ \dfrac{-1}{20}\)
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