TNPSC Group 4 · 2019
198. If \(a_1 = -1\) then find \(a_2,\ a_3\) in \(a_n = \dfrac{a_{n-1}}{n+2},\ n>1\ \forall\ n \in \mathbb{N}\).
Answer:
D.
\(\dfrac{-1}{4},\ \dfrac{-1}{20}\)