TNPSC Group 2 · 2025 Preliminary Examination
196. \(\dfrac{a}{b}=\dfrac{4}{5}\) மற்றும் \(\dfrac{b}{c}=\dfrac{15}{16}\) எனில் \(\dfrac{c^2-a^2}{c^2+a^2}=\)
Answer:
B.
\(\dfrac{7}{25}\)